What is the energy (in eV) of a photon in a monochromatic beam of light with a wavelength of 325.0325.0 nm? (Give your answer to two decimal places)
Question
What is the energy (in eV) of a photon in a monochromatic beam of light with a wavelength of 325.0 nm?
(Give your answer to two decimal places)
Solution
The energy of a photon can be calculated using the formula:
E = hc/λ
where: E is the energy of the photon, h is Planck's constant (4.135667696 x 10^-15 eV.s), c is the speed of light (299792458 m/s), and λ is the wavelength of the light.
First, we need to convert the wavelength from nanometers to meters. 1 nm = 10^-9 m, so:
λ = 325.0 nm = 325.0 x 10^-9 m = 3.25 x 10^-7 m
Now we can substitute the values into the formula:
E = (4.135667696 x 10^-15 eV.s x 299792458 m/s) / 3.25 x 10^-7 m E = 3.82 eV
So, the energy of a photon in a monochromatic beam of light with a wavelength of 325.0 nm is approximately 3.82 eV.
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