If magnetic flux passing through a coil as a function of time is given by = (2t2 + t) Wb, then induced emf (magnitude) at t = 1 s will be ______ V

The induced emf in a coil is given by Faraday's law of electromagnetic induction, which states that the induced emf is equal to the rate of change of magnetic flux.

Mathematically, it is given by:

e = -dΦ/dt

where: e is the induced emf, Φ is the magnetic flux, and t is the time.

Given that the magnetic flux Φ = 2t² + t, we can find the rate of change of flux with respect to time by differentiating Φ with respect to t.

dΦ/dt = d/dt (2t² + t) = 4t + 1

At t = 1 s, the rate of change of flux (and hence the induced emf) is:

e = -(4*1 + 1) = -5 V

However, since the question asks for the magnitude of the induced emf, we take the absolute value, which gives us 5 V.