If A,B,C𝐴,𝐵,𝐶 are successive even natural numbers in ascending order. Five times CC is eight more than seven times A. Find B?
Question
If A, B, C are successive even natural numbers in ascending order.
Five times C is eight more than seven times A.
Find B?
Solution
Given that A, B, and C are successive even natural numbers, we can express B and C in terms of A. Since they are even, we can say:
B = A + 2 C = A + 4
The problem also states that five times C is eight more than seven times A. We can express this as an equation:
5C = 7A + 8
Substitute C = A + 4 into the equation:
5(A + 4) = 7A + 8 5A + 20 = 7A + 8 2A = 12 A = 6
Substitute A = 6 into the equation B = A + 2 to find B:
B = 6 + 2 = 8
So, B is 8.
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