What is the acceleration of an object that is initially moving at 10.5m/s and is moving at 13.5m/s after 2.0s?
Question
What is the acceleration of an object that is initially moving at 10.5 m/s and is moving at 13.5 m/s after 2.0 s?
Solution
The acceleration of an object can be calculated using the formula:
a = (v_f - v_i) / t
where: a = acceleration v_f = final velocity v_i = initial velocity t = time
Given in the problem: v_f = 13.5 m/s v_i = 10.5 m/s t = 2.0 s
Substitute these values into the formula:
a = (13.5 m/s - 10.5 m/s) / 2.0 s a = 3.0 m/s / 2.0 s a = 1.5 m/s²
So, the acceleration of the object is 1.5 m/s².
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