pendulum of length 1m and period 2.01s is placed at the top of MountEveresthaving an altitude of 8849m. Calculate the value of ‘g’ at that poin

The period of a simple pendulum is given by the formula:

T = 2π√(L/g)

where: T = period of the pendulum L = length of the pendulum g = acceleration due to gravity

We can rearrange this formula to solve for g:

g = 4π²L/T²

Substituting the given values:

g = 4π²(1m)/(2.01s)²

Calculate the above expression to get the value of 'g' at the top of Mount Everest.

However, this is the value of 'g' without considering the altitude of Mount Everest. The value of 'g' decreases with altitude because the gravitational force decreases with distance from the center of the Earth.

The formula to adjust 'g' for altitude is:

g' = g(1 - 2h/R)

where: g' = adjusted acceleration due to gravity h = altitude R = radius of the Earth (approximately 6,371,000 m)

Substitute the given altitude and the calculated 'g' into this formula to get the adjusted value of 'g' at the top of Mount Everest.