The extension of the spring can be calculated using Hooke's Law, which states that the force (F) exerted by a spring is equal to the product of the spring constant (k) and the extension (x) of the spring. This can be written as:

F = k * x

We can rearrange this equation to solve for the extension (x):

x = F / k

Given that the spring constant (k) is 5 N/cm and the force (F) is 15 N, we can substitute these values into the equation:

x = 15 N / 5 N/cm = 3 cm

So, the extension of the spring when loaded with 15 N is 3 cm.

Question

The extension of the spring can be calculated using Hooke's Law, which states that the force (F) exerted by a spring is equal to the product of the spring constant (k) and the extension (x) of the spring. This can be written as:

F = k * x

We can rearrange this equation to solve for the extension (x):

x = F / k

Given that the spring constant (k) is 5 N/cm and the force (F) is 15 N, we can substitute these values into the equation:

x = 15 N / 5 N/cm = 3 cm

So, the extension of the spring when loaded with 15 N is 3 cm.

Knowee AI · Accepted Answer

The extension of the spring can be calculated using Hooke's Law, which states that the force (F) exerted by a spring is equal to the product of the spring constant (k) and the extension (x) of the spring. This can be written as:

F = k * x

We can rearrange this equation to solve for the extension (x):

x = F / k

Given that the spring constant (k) is 5 N/cm and the force (F) is 15 N, we can substitute these values into the equation:

x = 15 N / 5 N/cm = 3 cm

So, the extension of the spring when loaded with 15 N is 3 cm.

A spring has a spring constant of 5N/cm. What is its extension when loaded with 15N?2 marks4cm5cm3m3cm

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A spring has a spring constant of 5N/cm.

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