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In the complex K4[Th(C2O4)2(H2O)2]K4[ThC2O42H2O2] . If coordination number is X and oxidation number of Th is Y. The sum of X + Y is?

Question

In the complex K4[Th(C2O4)2(H2O)2]K4[ThC2O42H2O2]

If coordination number is X and oxidation number of Th is Y. The sum of X + Y is?

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Solution

The coordination number (X) is the number of atoms, ions, or molecules that a central atom or ion holds as its nearest neighbours in a complex or coordination compound or in a crystal. In this case, the coordination number of Th is 8 (4 from two bidentate oxalate ions and 2 from two water molecules).

The oxidation number (Y) is the charge that atom would have if the compound was composed of ions. In this case, the oxidation number of Th is +4.

So, the sum of X + Y is 8 + 4 = 12.

This problem has been solved

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