Two SHM is represented by y1=0.1 sin [100πt+π3 ] and y2=0.1 cos πt. The phase difference of the velocity of particle 1 with respect to 2 is
Question
Solution 1
The phase difference between two simple harmonic motions (SHMs) can be found by comparing their equations.
The given equations are:
y1 = 0.1 sin (100πt + π/3) and y2 = 0.1 cos πt
First, we need to find the velocities of the two particles. The velocity of a particle in SHM is given by the derivat Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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