The sum of three numbers is 264. If the first number be twice the 2nd , the third number be 1/3rd of the first, then the second number is ?
Question
The sum of three numbers is 264. If the first number be twice the 2nd, the third number be 1/3rd of the first, then the second number is ?
Solution
Let's solve this step by step:
Let's assume the second number is x.
According to the given information: The first number is twice the second number, so the first number is 2x. The third number is 1/3rd of the first number, so the third number is (1/3) * (2x) = (2/3)x.
The sum of the three numbers is 264, so we can write the equation: 2x + x + (2/3)x = 264
Combining like terms: (7/3)x = 264
To solve for x, we can multiply both sides of the equation by 3/7: x = (264 * 3/7)
Calculating the value of x: x = 112
Therefore, the second number is 112.
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