How long does it take for a golf ball to fall from rest for a distance of 14.0 m?

To solve this problem, we can use the equation of motion that relates distance, initial velocity, time, and acceleration due to gravity. The equation is:

d = vit + 0.5gt^2

where: d = distance (14.0 m) vi = initial velocity (0 m/s because the ball is at rest) g = acceleration due to gravity (approximately 9.8 m/s^2) t = time (what we're trying to find)

Substituting the known values into the equation, we get:

14.0 m = 0 m/s * t + 0.5 * 9.8 m/s^2 * t^2

Solving for t, we get:

t^2 = 2d / g t^2 = 2 * 14.0 m / 9.8 m/s^2 t^2 = 2.857 s^2

Taking the square root of both sides to solve for t, we get:

t = sqrt(2.857 s^2) t = 1.69 s

So, it takes approximately 1.69 seconds for a golf ball to fall from rest for a distance of 14.0 m.