According to Bohr’s model, the radius of Ne9+ ion in ground state should be (in Å)

According to Bohr's model, the radius of an electron orbit is given by the formula:

r = 0.529 * n^2/Z Å

where:

• r is the radius of the electron orbit
• n is the principal quantum number (for the ground state, n = 1)
• Z is the atomic number (for Ne, Z = 10)

However, you're asking for Ne9+, which means it has lost 9 electrons and only one remains. So, the effective atomic number Z for Ne9+ is 10 - 9 = 1.

Substituting these values into the formula, we get:

r = 0.529 * 1^2/1 = 0.529 Å

So, according to Bohr's model, the radius of the Ne9+ ion in the ground state should be 0.529 Å.