What will be the output of the following code? int main() {int x = 5;int * ptr = &x;*ptr + 1;cout << (*ptr)++;}
Question
Solution 1
The output of the code will be 5.
Here's the step by step explanation:
int x = 5;
This line declares an integer variablex
and assigns it the value 5.int * ptr = &x;
This line declares a pointerptr
and assigns it the address ofx
. Nowptr
is pointing tox
.*ptr + 1;
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