If H2SO4 follows Lewis octet rule then formal charge on sulphur isA+1 B+2 C0 D2

To calculate the formal charge of an atom in a molecule, the formula used is:

Formal charge = [# of valence electrons on atom] - [non-bonding valence electrons + 1/2 bonding electrons]

In the case of sulfur in H2SO4:

1. Sulfur is in group 6 on the periodic table, so it has 6 valence electrons.
2. In H2SO4, sulfur is bonded to four oxygen atoms and does not have any non-bonding electrons.
3. Each bond consists of 2 electrons, so sulfur has 4*2 = 8 bonding electrons.

Substituting these values into the formula gives:

Formal charge = 6 - (0 + 1/2 * 8) = 6 - 4 = +2

So, the formal charge on sulfur in H2SO4 is +2. Therefore, the correct answer is B+2.