If the solubility product of Mg3(PO4)2 equals 1.08x10-13, what is the value of [Mg2+] in the saturated solution?

To find the value of [Mg2+] in the saturated solution, we need to use the solubility product expression for Mg3(PO4)2. The solubility product expression is given by:

Ksp = [Mg2+]^3 [PO4]^-2

Given that the solubility product (Ksp) is 1.08x10^-13, we can substitute this value into the expression:

1.08x10^-13 = [Mg2+]^3 [PO4]^-2

Since the solubility product is very small, we can assume that the concentration of Mg2+ is much smaller than the concentration of PO4^-2. Therefore, we can neglect the contribution of [PO4]^-2 and simplify the expression to:

1.08x10^-13 = [Mg2+]^3

To solve for [Mg2+], we need to take the cube root of both sides of the equation:

[Mg2+] = (1.08x10^-13)^(1/3)

Calculating this value, we find that [Mg2+] is approximately 1.96x10^-5. Therefore, the value of [Mg2+] in the saturated solution is 1.96x10^-5.