If the solubility product of Mg3(PO4)2 equals 1.08x10-13, what is the value of [Mg2+] in the saturated solution?

Question

If the solubility product of Mg3(PO4)2 equals 1.08x10-13, what is the value of [Mg2+] in the saturated solution?
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Solution 1

To find the value of [Mg2+] in the saturated solution, we need to use the solubility product expression for Mg3(PO4)2. The solubility product expression is given by:

Ksp = [Mg2+]^3 [PO4]^-2

Given that the solubility product (Ksp) is 1.08x10^-13, we can substitute this value into the expression:

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