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Which one of the H-C bonds indicated would have the lowest bond dissociation energy?Select answer from the options belowH-CH3H-C(CH3)3 H-CH2CH3 H-CH(CH3)2

Question

Which one of the H-C bonds indicated would have the lowest bond dissociation energy?

Select answer from the options below

  • H-CH3
  • H-C(CH3)3
  • H-CH2CH3
  • H-CH(CH3)2
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Solution

The bond dissociation energy is the energy required to break a bond. It is influenced by several factors, including the size of the atoms involved in the bond, the type of bond (single, double, triple), and the surrounding molecular environment.

In this case, we are comparing the bond dissociation energies of different H-C bonds. The H-C bond with the lowest bond dissociation energy would be the one that is easiest to break.

  1. H-CH3: This is a bond between hydrogen and a carbon that is bonded to three other hydrogens.

  2. H-C(CH3)3: This is a bond between hydrogen and a carbon that is bonded to three methyl groups.

  3. H-CH2CH3: This is a bond between hydrogen and a carbon that is bonded to two hydrogens and one ethyl group.

  4. H-CH(CH3)2: This is a bond between hydrogen and a carbon that is bonded to one hydrogen and two methyl groups.

The bond dissociation energy is influenced by the steric hindrance around the carbon atom. Steric hindrance refers to the interference caused by the physical size of groups within a molecule, which can slow down or prevent reactions.

In this case, the H-C bond in H-C(CH3)3 would have the lowest bond dissociation energy because the carbon atom is surrounded by three bulky methyl groups. This steric hindrance makes it easier for the H-C bond to break.

This problem has been solved

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