Find the Fourier series of the function𝑓𝑥=-𝑘, -2<𝑥<0𝑘, 0<𝑥 <2 P = 2l = 4, l = 2
Question
Solution 1
The Fourier series of a function can be represented as:
f(x) = a0/2 + Σ [an cos(nπx/L) + bn sin(nπx/L)]
where the coefficients a0, an, and bn are given by:
a0 = (1/L) ∫ from -L to L [f(x) dx]
an = (1/L) ∫ from -L to L [f(x) cos(nπx/L) dx]
bn = (1/L) ∫ from -L to L [f(x) sin(nπx/L) dx]
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