The dimensions of dy/dx are the dimensions of pressure divided by the dimensions of velocity gradient.

The dimensions of pressure (P) are [M L^-1 T^-2], where M represents mass, L represents length, and T represents time.

The dimensions of velocity gradient (v) are [L T^-1].

So, the dimensions of dy/dx are [M L^-1 T^-2] / [L T^-1] = [M L^-2 T^-1].

However, the question asks for the dimensions of the second derivative, d²y/dx². This means we take the derivative of the first derivative with respect to x again.

The dimensions of dx are [L].

So, the dimensions of d²y/dx² are [M L^-2 T^-1] / [L] = [M L^-3 T^-1].

Question

The dimensions of dy/dx are the dimensions of pressure divided by the dimensions of velocity gradient.

The dimensions of pressure (P) are [M L^-1 T^-2], where M represents mass, L represents length, and T represents time.

The dimensions of velocity gradient (v) are [L T^-1].

So, the dimensions of dy/dx are [M L^-1 T^-2] / [L T^-1] = [M L^-2 T^-1].

However, the question asks for the dimensions of the second derivative, d²y/dx². This means we take the derivative of the first derivative with respect to x again.

The dimensions of dx are [L].

So, the dimensions of d²y/dx² are [M L^-2 T^-1] / [L] = [M L^-3 T^-1].

Knowee AI · Accepted Answer

The dimensions of dy/dx are the dimensions of pressure divided by the dimensions of velocity gradient.

The dimensions of pressure (P) are [M L^-1 T^-2], where M represents mass, L represents length, and T represents time.

The dimensions of velocity gradient (v) are [L T^-1].

So, the dimensions of dy/dx are [M L^-1 T^-2] / [L T^-1] = [M L^-2 T^-1].

However, the question asks for the dimensions of the second derivative, d²y/dx². This means we take the derivative of the first derivative with respect to x again.

The dimensions of dx are [L].

So, the dimensions of d²y/dx² are [M L^-2 T^-1] / [L] = [M L^-3 T^-1].

f 𝑦 represent pressure and 𝑥 representsvelocity gradient, then the dimensionsof 𝑑2𝑦𝑑𝑥2 are

Question

If 𝑦 represents pressure and 𝑥 represents velocity gradient, then the dimensions of $\frac{d^2 y}{dx^2}$ are

Solution

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