Solve the equation 6, x, squared, plus, 6, x, minus, 13, equals, 06x 2 +6x−13=0 to the nearest tenth.
Question
Solution 1
Claro, vamos a resolver la ecuación paso a paso.
La ecuación dada es: [ 6x^2 + 6x - 13 = 0 ]
Para resolver esta ecuación cuadrática, utilizaremos la fórmula cuadrática: [ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ]
En esta ecuación, los coeficientes son: [ a = 6 ] [ b = 6 ] [ c = -13 ]
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