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The equation of a line is given by 𝑦=𝑎(𝑥−5)+4.If the 𝑦-intercept is −6, find the value of 𝑎.

Question

The equation of a line is given by

y=a(x5)+4 y = a(x - 5) + 4
If the y y -intercept is 6 -6 , find the value of a a .

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Solution

1. Break Down the Problem

We have the equation of the line y=a(x5)+4 y = a(x - 5) + 4 and we need to find the value of a a given that the y y -intercept is 6-6. The y y -intercept occurs when x=0 x = 0 .

2. Relevant Concepts

The y y -intercept can be found by substituting x=0 x = 0 into the equation of the line. The point of intersection with the y y -axis is given by the coordinates (0,c)(0, c), where c c is the y y -intercept.

3. Analysis and Detail

Substituting x=0 x = 0 into the equation:

y=a(05)+4 y = a(0 - 5) + 4

This simplifies to:

y=a(5)+4 y = a(-5) + 4 y=5a+4 y = -5a + 4

Since we know the y y -intercept is 6-6, we can set up the following equation:

5a+4=6 -5a + 4 = -6

4. Verify and Summarize

Now, we will solve for a a :

5a+4=65a=645a=10a=105a=2 -5a + 4 = -6 \\ -5a = -6 - 4 \\ -5a = -10 \\ a = \frac{-10}{-5} \\ a = 2

Final Answer

The value of a a is 2 2 .

This problem has been solved

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