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The voltage and current in a capacitor are related asa.i=Cdv/dtb.i=Cdt/dvc.v=Cdt/dvd.v=Cdv/dt

Question

The voltage and current in a capacitor are related as

  • i = C * dv/dt
  • b.i = C * dt/dvc
  • v = C * dt/dv
  • d.v = C * dv/dt
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Solution

The relationship between voltage and current in a capacitor is given by the equation i = C dv/dt.

Here's a step-by-step explanation:

  1. The symbol 'i' represents the current flowing through the capacitor.

  2. 'C' is the capacitance of the capacitor, which is a measure of how much charge it can store per unit voltage.

  3. 'v' is the voltage across the capacitor.

  4. 'dv/dt' is the rate of change of voltage with respect to time.

So, the equation i = C dv/dt means that the current flowing through the capacitor is equal to the capacitance times the rate of change of voltage.

This equation is a result of the definition of capacitance (C = q/v, where q is the charge stored in the capacitor) and the relationship between current and charge (i = dq/dt, where dq/dt is the rate of change of charge with respect to time). By substituting these definitions into the equation, we get i = C dv/dt.

The other equations you mentioned (i = C dt/dv, v = C dt/dv, and v = C dv/dt) are not correct. The correct relationship is i = C dv/dt.

This problem has been solved

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