The voltage and current in a capacitor are related asa.i=Cdv/dtb.i=Cdt/dvc.v=Cdt/dvd.v=Cdv/dt
Question
The voltage and current in a capacitor are related as
i = C * dv/dt
b.i = C * dt/dvc
v = C * dt/dv
d.v = C * dv/dt
Solution
The relationship between voltage and current in a capacitor is given by the equation i = C dv/dt.
Here's a step-by-step explanation:
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The symbol 'i' represents the current flowing through the capacitor.
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'C' is the capacitance of the capacitor, which is a measure of how much charge it can store per unit voltage.
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'v' is the voltage across the capacitor.
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'dv/dt' is the rate of change of voltage with respect to time.
So, the equation i = C dv/dt means that the current flowing through the capacitor is equal to the capacitance times the rate of change of voltage.
This equation is a result of the definition of capacitance (C = q/v, where q is the charge stored in the capacitor) and the relationship between current and charge (i = dq/dt, where dq/dt is the rate of change of charge with respect to time). By substituting these definitions into the equation, we get i = C dv/dt.
The other equations you mentioned (i = C dt/dv, v = C dt/dv, and v = C dv/dt) are not correct. The correct relationship is i = C dv/dt.
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