Write a Python program that matches a string that has an 'a' followed by anything, ending in 'b'
Question
Write a Python program that matches a string that has an 'a' followed by anything, ending in 'b'.
Solution
Sure, here is a Python program that matches a string that has an 'a' followed by anything, ending in 'b':
import re
def match_string(s):
pattern = 'a.*b$'
if re.search(pattern, s):
return True
else:
return False
# Test the function
print(match_string('abc')) # True
print(match_string('a123b')) # True
print(match_string('ab')) # True
print(match_string('acb')) # True
print(match_string('bca')) # False
In this program, we first import the re
module, which provides support for regular expressions in Python. We then define a function match_string
that takes a string s
as input.
Inside the function, we define a pattern 'a.*b$'
to match. This pattern matches any string that starts with 'a', followed by any number of any characters (denoted by .*
), and ends with 'b' (denoted by b$
).
We then use the re.search
function to search for this pattern in the input string s
. If the pattern is found, re.search
returns a match object, which is truthy, so the function returns True
. If the pattern is not found, re.search
returns None
, which is falsy, so the function returns False
.
Finally, we test the function with some example strings.
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