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Write a Python program that matches a string that has an 'a' followed by anything, ending in 'b'

Question

Write a Python program that matches a string that has an 'a' followed by anything, ending in 'b'.

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Solution

Sure, here is a Python program that matches a string that has an 'a' followed by anything, ending in 'b':

import re

def match_string(s):
    pattern = 'a.*b$'
    if re.search(pattern, s):
        return True
    else:
        return False

# Test the function
print(match_string('abc'))  # True
print(match_string('a123b'))  # True
print(match_string('ab'))  # True
print(match_string('acb'))  # True
print(match_string('bca'))  # False

In this program, we first import the re module, which provides support for regular expressions in Python. We then define a function match_string that takes a string s as input.

Inside the function, we define a pattern 'a.*b$' to match. This pattern matches any string that starts with 'a', followed by any number of any characters (denoted by .*), and ends with 'b' (denoted by b$).

We then use the re.search function to search for this pattern in the input string s. If the pattern is found, re.search returns a match object, which is truthy, so the function returns True. If the pattern is not found, re.search returns None, which is falsy, so the function returns False.

Finally, we test the function with some example strings.

This problem has been solved

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