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In ΔWXY, w = 470 inches, mm∠W=55° and mm∠X=42°. Find the length of y, to the nearest 10th of an inch.

Question

In ΔWXY,

  • w = 470 inches,
  • W=55 \angle W = 55^{\circ}
  • X=42 \angle X = 42^{\circ}

Find the length of y, to the nearest 10th of an inch.

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Solution

To solve this problem, we can use the Law of Sines. The Law of Sines states that the ratio of the length of a side of a triangle to the sine of its opposite angle is the same for all three sides of the triangle.

Here's how you can apply it:

  1. First, find the measure of angle Y. Since the sum of the angles in a triangle is 180°, you can subtract the measures of angle W and angle X from 180°.

    ∠Y = 180° - 55° - 42° = 83°

  2. Now, you can use the Law of Sines to find the length of side y. Set up the equation like this:

    w/sin(W) = y/sin(Y)

  3. Substitute the given values into the equation:

    470/sin(55°) = y/sin(83°)

  4. Solve the equation for y:

    y = (470 * sin(83°)) / sin(55°)

  5. Calculate the value of y to find the length of side y to the nearest tenth of an inch.

Remember to use your calculator's degree mode for the trigonometric calculations.

This problem has been solved

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