In ΔHIJ, i = 2.8 inches, mm∠I=68° and mm∠J=50°. Find the length of j, to the nearest 10th of an inch.
Question
In ΔHIJ,
- i = 2.8 inches,
- mm∠I = 68°
- mm∠J = 50°.
Find the length of j, to the nearest 10th of an inch.
Solution
To find the length of side j in triangle HIJ, we can use the Law of Sines. The Law of Sines states that the ratio of the length of a side of a triangle to the sine of its opposite angle is the same for all three sides of the triangle.
Here's how you can apply it:
-
First, find the measure of angle H. Since the sum of the angles in a triangle is 180°, you can subtract the given angles from 180° to find angle H.
So, m∠H = 180° - 68° - 50° = 62°
-
Now, you can set up the ratio of the sides to the sines of their opposite angles. According to the Law of Sines,
i/sin(I) = j/sin(J)
Substitute the given values into the equation:
2.8/sin(68°) = j/sin(50°)
-
Solve the equation for j:
j = (2.8/sin(68°)) * sin(50°)
-
Calculate the value:
j ≈ 2.3 inches
So, the length of side j is approximately 2.3 inches.
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