Using inverse square law. If the distance between two masses is doubled, explain the effect on the magnitude of the force changed in terms of F.A
Question
Using inverse square law. If the distance between two masses
is doubled, explain the effect on the
magnitude of the force changed in terms of F.A.
Solution
The inverse square law states that a specified physical quantity or intensity is inversely proportional to the square of the distance from the source of that physical property. In the context of gravity, the force between two masses is given by the equation:
F = G * (m1 * m2) / r^2
where:
- F is the force between the masses,
- G is the gravitational constant,
- m1 and m2 are the two masses, and
- r is the distance between the centers of the two masses.
If the distance between the two masses (r) is doubled, then the new force (F') is given by:
F' = G * (m1 * m2) / (2r)^2 = G * (m1 * m2) / 4r^2 = F / 4
So, if the distance between the two masses is doubled, the force between them is reduced to one-fourth of its original value. In terms of F.A, the force is inversely proportional to the square of the distance, so if the distance is doubled (2A), the force becomes F/(2^2) = F/4.
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