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Using inverse square law. If the distance between two masses  is doubled, explain the effect on the  magnitude of the force changed in terms of F.A

Question

Using inverse square law. If the distance between two masses

is doubled, explain the effect on the
magnitude of the force changed in terms of F.A.

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Solution

The inverse square law states that a specified physical quantity or intensity is inversely proportional to the square of the distance from the source of that physical property. In the context of gravity, the force between two masses is given by the equation:

F = G * (m1 * m2) / r^2

where:

  • F is the force between the masses,
  • G is the gravitational constant,
  • m1 and m2 are the two masses, and
  • r is the distance between the centers of the two masses.

If the distance between the two masses (r) is doubled, then the new force (F') is given by:

F' = G * (m1 * m2) / (2r)^2 = G * (m1 * m2) / 4r^2 = F / 4

So, if the distance between the two masses is doubled, the force between them is reduced to one-fourth of its original value. In terms of F.A, the force is inversely proportional to the square of the distance, so if the distance is doubled (2A), the force becomes F/(2^2) = F/4.

This problem has been solved

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