Calculate the hardness in terms of CaCO3 Equivalent if 16.8mg/l Mg (HCO3)2 is present in water sample.a.40 mg/lb.16.8 mg/lc.11 mg/ld.11.5 mg/l
Question
Calculate the hardness in terms of CaCO3 Equivalent if 16.8mg/l Mg (HCO3)2 is present in water sample.
- a. 40 mg/l
- b. 16.8 mg/l
- c. 11 mg/l
- d. 11.5 mg/l
Solution
The hardness of water due to the presence of magnesium bicarbonate [Mg(HCO3)2] can be calculated using the formula:
Hardness (as CaCO3) = Quantity of Ion (mg/l) * Equivalent weight of CaCO3 / Equivalent weight of Ion
The equivalent weight of CaCO3 (Calcium Carbonate) is 50.
The equivalent weight of Mg(HCO3)2 (Magnesium Bicarbonate) is 73.
Given that the quantity of Mg(HCO3)2 in the water sample is 16.8 mg/l, we can substitute these values into the formula:
Hardness (as CaCO3) = 16.8 mg/l * 50 / 73
Solving this gives us a hardness of approximately 11.5 mg/l as CaCO3.
So, the correct answer is d. 11.5 mg/l.
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