To the nearest tenth of a second, how long was the ball in the air before Jen hit it?

To solve the problem, we need more details about the scenario, such as the height from which the ball was dropped, the type of motion (e.g., free fall), and any other relevant variables (like initial velocity or whether it was thrown). However, I will outline a general approach to calculate the time a ball is in the air.

1. Break Down the Problem

• Identify the height (h) from which the ball is released.
• Determine if the ball is dropped or thrown, as this affects the calculation.
• Use the appropriate physics equations for motion under gravity.

2. Relevant Concepts

• For free fall, use the equation: $h = \frac{1}{2}gt^2$ where:
  • $h$ = height (meters)
  • $g$ = acceleration due to gravity (approximately $9.81 \, \text{m/s}^2$)
  • $t$ = time in seconds (to be calculated)

3. Analysis and Detail

• Rearranging the formula to find $t$: $t = \sqrt{\frac{2h}{g}}$
• Substitute $h$ into the equation.

4. Verify and Summarize

• After calculating for $t$, round the result to the nearest tenth of a second.

Final Answer

• Without the actual height value, I can't provide a precise time. If we assume, for example, the ball was dropped from a height of 4.9 meters: $t = \sqrt{\frac{2 \cdot 4.9}{9.81}} \approx \sqrt{1} \approx 1.0 \, \text{seconds}$
• Therefore, if the ball was dropped from 4.9 meters, it was in the air for approximately 1.0 seconds. Please provide further details for an accurate calculation.