Knowee
Questions
Features
Study Tools

Understanding Comma operator#include <stdio.h>int main(void) { int a; a = (1, 2, 3); printf("%d", a); return 0;}What is the value of a =

Question

Understanding Comma operator

#include &lt;stdio.h&gt;
int main(void) {
	int a;
	a = (1, 2, 3);
	printf(&quot;%d&quot;, a);
	return 0;
}

What is the value of a =

🧐 Not the exact question you are looking for?Go ask a question

Solution

Understanding the Comma Operator in C

  1. Break Down the Problem

    • The code snippet provided uses the comma operator in C programming.
    • We need to determine the value assigned to variable a when the line a = (1, 2, 3); is executed.
  2. Relevant Concepts

    • In C, the comma operator evaluates its first operand (in this case, 1), discards the result, then evaluates its second operand (2), discards that result as well, and finally evaluates the third operand (3), which becomes the result of the expression.
  3. Analysis and Detail

    • The expression (1, 2, 3) means:
      • Evaluate 1 → discarded
      • Evaluate 2 → discarded
      • Evaluate 3 → this is the final result.
    • Therefore, the value assigned to a is 3.
  4. Verify and Summarize

    • After evaluating the expression using the comma operator, we confirm that the final value assigned to a is indeed 3.

Final Answer

The value of a is 3.

This problem has been solved

Similar Questions

Understanding Comma operator#include <stdio.h>int main(void) { int a; a = (1, 2, 3); printf("%d", a); return 0;}What is the value of a =

The operator used to get value at address stored in a pointer variable isa.*b.&c.&&d.||

What is the output of the following code?#include <stdio.h>int main() {    int i = 0;    for (; i < 5; i++);    printf("%d ", i);    return 0;}

Understanding Unary operators#include <stdio.h>void main() { int a = 10, b; b = a++ + ++a; printf("%d %d\n", a, b);}What is the a = b =

Which of these is used after a nominative absolute?ColonQuestion markFull stopComma

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.