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The equation of a circle is given below. Identify the center and radius. Then graph the circle.=+x2−y224

Question

The equation of a circle is given below. Identify the center and radius. Then graph the circle.

x^2 - y = 24

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Solution

1. Break Down the Problem

We need to rewrite the equation of the circle in standard form to identify the center and radius. The standard form of a circle's equation is given by:

(xh)2+(yk)2=r2 (x - h)^2 + (y - k)^2 = r^2

where (h,k)(h, k) is the center and rr is the radius. The equation given is:

x2y2=24 x^2 - y^2 = 24

2. Relevant Concepts

To convert the given equation to standard form, we can manipulate it as follows:

  1. Rearrange the equation to isolate terms related to xx and yy.
  2. This may involve completing the square if necessary (but in this case, it's not needed).

3. Analysis and Detail

Starting with the equation:

x2y2=24 x^2 - y^2 = 24

This is not the standard form of a circle. To see if there is a circle in this equation, we can rearrange it slightly:

x2+(y)2=24 x^2 + (-y)^2 = 24

This can be rewritten as:

(x0)2+(y0)2=24 (x - 0)^2 + (y - 0)^2 = 24

However, we recognize this typically represents hyperbolic structures due to the signs of x2x^2 and y2y^2. Hence, this expression does not correspond to a circle.

4. Verify and Summarize

Since the term y2y^2 has a negative coefficient, the expression is indicative of a hyperbola instead of a circle. Therefore, there is no center or radius in the context of a circle.

Final Answer

This equation does not represent a circle, so there is no identifiable center or radius. Instead, it represents a hyperbola.

This problem has been solved

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