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The equation of a circle is given below. Identify the center and the radius. Then graph the circle.=+x2+4y−y2210

Question

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Solution

To analyze the given equation of the circle, let's first rewrite it for clarity:

The equation provided is: x2+4yy2=210 x^2 + 4y - y^2 = 210

1. Break Down the Problem

We need to:

  1. Rearrange the equation to standard form of a circle.
  2. Identify the center and radius from the standard form.
  3. Graph the circle.

2. Relevant Concepts

The standard form of a circle's equation is: (xh)2+(yk)2=r2 (x - h)^2 + (y - k)^2 = r^2 where (h,k)(h, k) is the center and rr is the radius.

3. Analysis and Detail

Starting with the given equation: x2y2+4y=210 x^2 - y^2 + 4y = 210 We need to rearrange and complete the square for the yy terms.

  1. Rearranging the equation: x2(y24y)=210 x^2 - (y^2 - 4y) = 210

  2. Completing the square on y24yy^2 - 4y:

    • Take 4/2=2-4/2 = -2 and square it to get 44.
    • Rewrite: x2(y24y+44)=210 x^2 - (y^2 - 4y + 4 - 4) = 210
    • This simplifies to: x2(y2)2+4=210 x^2 - (y - 2)^2 + 4 = 210
    • Further simplifying gives: x2(y2)2=206 x^2 - (y - 2)^2 = 206
  3. Rearranging into standard form: (y2)2+x2=206 (y - 2)^2 + x^2 = 206

Now, we can identify the center and radius:

  • Center: (0,2)(0, 2)
  • Radius: r=206r = \sqrt{206}

4. Verify and Summarize

To summarize:

  • The center of the circle is at (0,2)(0, 2).
  • The radius is 206\sqrt{206}.

Final Answer

  • Center: (0,2)(0, 2)
  • Radius: 206\sqrt{206}

You can graph this circle centered at (0,2)(0, 2) with a radius of approximately 14.3514.35.

This problem has been solved

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