The area of a rectangle is given by 6x2y + 4y2x andthe width of the rectangle is given by 2xy. Find theperimeter of rectangle.
Question
The area of a rectangle is given by:
The width of the rectangle is given by:
Find the perimeter of the rectangle.
Solution
To find the perimeter of the rectangle, we first need to find the length of the rectangle. We know that the area of a rectangle is given by the formula:
Area = Length * Width
Given that the area is 6x^2y + 4y^2x and the width is 2xy, we can find the length by rearranging the formula to:
Length = Area / Width
Substituting the given values, we get:
Length = (6x^2y + 4y^2x) / 2xy
Simplify the equation by dividing each term by 2xy:
Length = 3x + 2y
Now that we have the length and the width of the rectangle, we can find the perimeter using the formula:
Perimeter = 2 * (Length + Width)
Substituting the values we found:
Perimeter = 2 * ((3x + 2y) + 2xy)
Simplify the equation to get the perimeter:
Perimeter = 2 * (3x + 2y + 2xy)
So, the perimeter of the rectangle is 2 * (3x + 2y + 2xy).
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