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The area of a rectangle is given by 6x2y + 4y2x andthe width of the rectangle is given by 2xy. Find theperimeter of rectangle.

Question

The area of a rectangle is given by:

6x2y+4y2x 6x^2y + 4y^2x

The width of the rectangle is given by:

2xy 2xy

Find the perimeter of the rectangle.

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Solution

To find the perimeter of the rectangle, we first need to find the length of the rectangle. We know that the area of a rectangle is given by the formula:

Area = Length * Width

Given that the area is 6x^2y + 4y^2x and the width is 2xy, we can find the length by rearranging the formula to:

Length = Area / Width

Substituting the given values, we get:

Length = (6x^2y + 4y^2x) / 2xy

Simplify the equation by dividing each term by 2xy:

Length = 3x + 2y

Now that we have the length and the width of the rectangle, we can find the perimeter using the formula:

Perimeter = 2 * (Length + Width)

Substituting the values we found:

Perimeter = 2 * ((3x + 2y) + 2xy)

Simplify the equation to get the perimeter:

Perimeter = 2 * (3x + 2y + 2xy)

So, the perimeter of the rectangle is 2 * (3x + 2y + 2xy).

This problem has been solved

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