Defined that x#y = x2 + y2 - xy, then 3#(2#4) = – 117 117 171 -171 None of these
Question
Solution 1
To solve this problem, we first need to calculate the value of 2#4 using the given definition of x#y = x^2 + y^2 - xy.
So, 2#4 = 2^2 + 4^2 - 2*4 = 4 + 16 - 8 = 12.
Next, we substitute this value into the expression 3#(2#4) to get 3#12.
So, 3#12 = 3^2 + 12^2 - 3*12 = 9 + 144 - 36 = 117.
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Defined that x#y = x2 + y2 - xy, then 3#(2#4) = – 117 117 171 -171 None of these