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Write the first six terms of the sequence, $f\left(n\right)=-n^3$f(n)=−n3​ .The first six terms of the sequence are , , , , , and .

Question

Write the first six terms of the sequence, f(n)=n3f(n)=-n^3.

The first six terms of the sequence are , , , , , and .

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Solution

To find the first six terms of the sequence defined by the function f(n)=n3 f(n) = -n^3 , we will substitute n n with the values from 1 to 6.

Steps:

  1. Calculate f(1) f(1) : f(1)=13=1 f(1) = -1^3 = -1

  2. Calculate f(2) f(2) : f(2)=23=8 f(2) = -2^3 = -8

  3. Calculate f(3) f(3) : f(3)=33=27 f(3) = -3^3 = -27

  4. Calculate f(4) f(4) : f(4)=43=64 f(4) = -4^3 = -64

  5. Calculate f(5) f(5) : f(5)=53=125 f(5) = -5^3 = -125

  6. Calculate f(6) f(6) : f(6)=63=216 f(6) = -6^3 = -216

Final Answer

The first six terms of the sequence are: 1,8,27,64,125,216 -1, -8, -27, -64, -125, -216

This problem has been solved

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