Write the first six terms of the sequence.$f\left(n\right)=\left(-2\right)^{n+1}$f(n)=(−2)n+1The first six terms of the sequence are , , ,
Question
Solution 1
To find the first six terms of the sequence defined by $f(n)=(-2)^{n+1}$, we substitute the values of n from 1 to 6 into the function:
- For n=1, $f(1)=(-2)^{1+1}=(-2)^2=4$
- For n=2, $f(2)=(-2)^{2+1}=(-2)^3=-8$
- For n=3, $f(3)=(-2)^{3+1}=(-2)^4=16$
- For n=4, $f(4)=(-2)^{4+1}=(-2)^5=-32$
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