Write the first six terms of the sequence, $f\left(n\right)=\frac{n}{4n-2}$f(n)=n4n−2 .The first six terms of the sequence are , , , , , and .
Question
Write the first six terms of the sequence,
f(n)=\frac{n}{4n-2}
The first six terms of the sequence are , , , , , and .
Solution
To find the first six terms of the sequence, we substitute the values of n from 1 to 6 into the function f(n) = n/(4n-2).
- For n=1, f(1) = 1/(4*1-2) = 1/2
- For n=2, f(2) = 2/(4*2-2) = 2/6 = 1/3
- For n=3, f(3) = 3/(4*3-2) = 3/10
- For n=4, f(4) = 4/(4*4-2) = 4/14 = 2/7
- For n=5, f(5) = 5/(4*5-2) = 5/18
- For n=6, f(6) = 6/(4*6-2) = 6/22 = 3/11
So, the first six terms of the sequence are 1/2, 1/3, 3/10, 2/7, 5/18, and 3/11.
Similar Questions
Write the first six terms of the sequence.$f\left(n\right)=\left(-2\right)^{n+1}$f(n)=(−2)n+1The first six terms of the sequence are , , ,
Find the first four terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.an = 6n2 + 9n − 6
Write the first six terms of the sequence.$a_n=3n-1$an=3n−1The first six terms of the sequence are , , , , ,
Find the first three terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.an = –n2 + 4n − 8
Write the first six terms of the sequence, $f\left(n\right)=-n^3$f(n)=−n3 .The first six terms of the sequence are , , , , , and .
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.