Find the number of distinct arrangements of the 9 letters in BEGINNING.Two of the same letter are considered identical (not distinct).
Question
Solution 1
To solve this problem, we use the formula for permutations of multiset: n! / (r1! * r2! * ... * rk!), where n is the total number of items, and r1, r2, ..., rk are the numbers of each type of item.
In the word BEGINNING, there are 9 letters in total.
- There are 3 N's.
- There are 2 G's.
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