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What is the output of the following code?char str1[] = "C programming";char str2[20];strcpy(str2, str1);printf("%s\n", str2);

Question

What is the output of the following code?

char str1[] = "C programming";
char str2[20];
strcpy(str2, str1);
printf("%s\n", str2);
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Solution

The output of the code will be "C programming".

Here's the step by step explanation:

  1. The code first declares a character array str1[] and initializes it with the string "C programming".

  2. Then it declares another character array str2[20] without initializing it.

  3. The strcpy(str2, str1); function is then called. This function copies the string pointed to by str1 (source) to str2 (destination).

  4. Finally, printf("%s\n", str2); prints the string that str2 is pointing to, which is now "C programming" due to the previous strcpy operation.

So, "C programming" is printed to the standard output.

This problem has been solved

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