Find the particular solution of this differential equation with initial conditions y(0)=1: y' = y/(3x-y^2)

Question

Find the particular solution of this differential equation with initial conditions y(0)=1: y' = y/(3x-y^2)
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

Para encontrar la solución particular de la ecuación diferencial dada con las condiciones iniciales, seguimos estos pasos:

  1. Ecuación diferencial dada: [ y' = \frac{y}{3x - y^2} ]

  2. Condición inicial: [ y(0) = 1 ]

  3. Separación de variables: Reescribimos la Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

Find the particular solution of this differential equation with initial conditions y(0)=1: (y' = y:(3x-y^2))

Find the particular solution of this differential equation with initial conditions y(0)=1: y' = y/(3x-y^2)

Find the solution of the differential equation that satisfies the given initial condition.dydx = xy, y(0) = −1

Find the general solution of this differential equation with separable variables: ((3e^x)sin y dx + (1 - e^x)cos ydy = 0)

Solve the differential equation 𝑑 𝑦 𝑑 𝑥 = 2 𝑥 dx dy ​ =2x with initial condition 𝑦 ( 0 ) = 3 y(0)=3.

1/3