Find the particular solution of this differential equation with initial conditions y(0)=1: y' = y/(3x-y^2)
Question
Solution 1
Para encontrar la solución particular de la ecuación diferencial dada con las condiciones iniciales, seguimos estos pasos:
Ecuación diferencial dada: [ y' = \frac{y}{3x - y^2} ]
Condición inicial: [ y(0) = 1 ]
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