What is the period of y = 3cos ( 4x + π/2) + 5?Question 4Select one:a.π/4b.π/2c.πd.2πe.–π
Question
Solution 1
The period of a cosine function is given by the formula 2π / |B|, where B is the coefficient of x in the argument of the cosine function.
In the given function y = 3cos (4x + π/2) + 5, the coefficient of x is 4.
So, the period of the function is 2π / |4| = 2π / 4 = π/2.
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