Let arcsin : [−1, 1] → [−π/2, π/2] be the inverse function of sin : [−π/2, π/2] → [−1, 1]. Showthat arcsin is differentiable on (−1, 1)
Question
Solution 1
To show that arcsin is differentiable on (-1,1), we need to show that its derivative exists on this interval.
Step 1: Define the function Let's define the function f(x) = arcsin(x). We want to find f'(x).
Step 2: Use the definition of the derivative The derivative of a function at a certain point Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv
Similar Questions
Let f : [0, π] → R be defined byf (x) =(0 if x = 0,x sin 1x − 1x cos 1x if x̸ = 0.Is f continuous?
Let arcsin : [−1, 1] → [−π/2, π/2] be the inverse function of sin : [−π/2, π/2] → [−1, 1]. Showthat arcsin is differentiable on (−1, 1)
Let f(x) be a differentiable function in the interval (0,2), then the value of ∫20f(x)dx
Let f:[−π2,π2]→R be a differentiable function such that f(0)=12, If the limx→0x∫x0f(t)dtex2−1=α,then 8α2 is equal to :
Consider the following function: f(x) = { sin x , if 0 ≤ x ≤ π 4 cos x , if π 4 ≤ x ≤ π 2 . Expand f(x) in a Fourier series of sine terms.