Calculate the entropy change when a sample of 30 g of Ne is expanded from 1 L to 10L and simultaneously cooled from 350 K to 300 K. Cv = 3/2

Question

Calculate the entropy change when a sample of 30 g of Ne is expanded from 1 L to 10L and simultaneously cooled from 350 K to 300 K. Cv = 3/2
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Solution 1

To calculate the entropy change, we can use the formula:

ΔS = Cv * ln(T2/T1) + R * ln(V2/V1)

Given that the sample of Ne is expanded from 1 L to 10 L and cooled from 350 K to 300 K, we can substitute the values into the formula.

ΔS = (3/2) * ln(300/350) + R * ln(10/1)

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