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Suppose ∑ni=1 bi xi = Z; we multiply the numerator and denominator by exp(z) toobtain Equation (2)

Question

Suppose i=1nbixi=Z \sum_{i=1}^{n} b_i x_i = Z ; we multiply the numerator and denominator by exp(Z) \exp(Z) to obtain Equation (2)

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Solution

To rewrite the equation by multiplying the numerator and the denominator by exp(Z)\exp(Z), we can go through the following steps:

  1. Identify the Original Expression: The original expression given is: i=1nbixi=Z \sum_{i=1}^{n} b_i x_i = Z

  2. Multiply Numerator and Denominator by exp(Z)\exp(Z): We want to multiply both sides of the equation by exp(Z)\exp(Z). For a fraction, this would generally look like: i=1nbixi1exp(Z)exp(Z)=Zexp(Z)exp(Z) \frac{\sum_{i=1}^{n} b_i x_i}{1} \cdot \frac{\exp(Z)}{\exp(Z)} = Z \cdot \frac{\exp(Z)}{\exp(Z)} which simplifies to: exp(Z)i=1nbixiexp(Z) \frac{\exp(Z) \sum_{i=1}^{n} b_i x_i}{\exp(Z)}

  3. Simplify: Since Z=i=1nbixiZ = \sum_{i=1}^{n} b_i x_i, we can replace ZZ back in the equation: exp(Z)Zexp(Z)=Z \frac{\exp(Z) Z}{\exp(Z)} = Z

  4. Conclusion: Thus, the equation transforms accordingly but retains its value.

Final Answer

The modified equation becomes: exp(Z)i=1nbixiexp(Z)=Z \frac{\exp(Z) \sum_{i=1}^{n} b_i x_i}{\exp(Z)} = Z

This problem has been solved

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