Find the equation of the line that passes through the points (−24,−18)(−24,−18) and (−12,−15)(−12,−15). Give your answer in the form: 𝑎𝑥+𝑏𝑦+𝑐ax+by+c==00

To find the equation of the line that passes through two points, we first need to find the slope of the line. The formula for the slope (m) is:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Substituting the given points (-24, -18) and (-12, -15) into the formula, we get:

m = (-15 - (-18)) / (-12 - (-24)) m = 3 / 12 m = 1/4

Next, we use the point-slope form of the equation of a line, which is:

y - y1 = m(x - x1)

Substituting m = 1/4 and the coordinates of one of the points into the equation, we get:

y - (-18) = 1/4(x - (-24)) y + 18 = 1/4x + 6

To get the equation in the form ax + by + c = 0, we rearrange the equation to:

1/4x - y - 12 = 0

Multiplying through by 4 to get rid of the fraction, we get:

x - 4y - 48 = 0

So, the equation of the line that passes through the points (-24, -18) and (-12, -15) is x - 4y - 48 = 0.