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Find the derivative of the y=ln(11x+41)๐‘ฆ=๐‘™๐‘›(11๐‘ฅ+41)Question 1Answera. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=11(11๐‘ฅ+41)b. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=11(๐‘ฅ+41)c. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=41(๐‘ฅ+41)d. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=41(11๐‘ฅ+41)e.

Question

Find the derivative of the y=ln(11x+41)

Question 1
Answer
a. dydx=11(11x+41) \frac{dy}{dx}=\frac{11}{(11x+41)}
b. dydx=11(x+41) \frac{dy}{dx}=\frac{11}{(x+41)}
c. dydx=41(x+41) \frac{dy}{dx}=\frac{41}{(x+41)}
d. dydx=41(11x+41) \frac{dy}{dx}=\frac{41}{(11x+41)}
e.

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Solution

The derivative of y=ln(11x+41) can be found using the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.

Step 1: Identify the outer and inner functions. Here, the outer function is ln(x) and the inner function is 11x+41.

Step 2: Find the derivative of the outer function. The derivative of ln(x) is 1/x.

Step 3: Find the derivative of the inner function. The derivative of 11x+41 is 11.

Step 4: Apply the chain rule. According to the chain rule, the derivative of y=ln(11x+41) is (1/(11x+41)) * 11.

So, the derivative of y=ln(11x+41) is 11/(11x+41). This corresponds to option a. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=11/(11๐‘ฅ+41).

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Find the derivative of the y=ln(11x+41)๐‘ฆ=๐‘™๐‘›(11๐‘ฅ+41)Question 1Answera. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=11(11๐‘ฅ+41)b. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=11(๐‘ฅ+41)c. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=41(๐‘ฅ+41)d. ๐‘‘๐‘ฆ๐‘‘๐‘ฅ=41(11๐‘ฅ+41)e.

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