What is the acceleration of an object that is moving at 45m/s initially, 36m/s after 2.0s and 27m/s after 4.0s?

The acceleration of an object can be calculated using the formula:

a = (v_f - v_i) / t

where: a = acceleration v_f = final velocity v_i = initial velocity t = time

In this case, we have two time intervals to consider:

1. From 0 to 2.0s: The initial velocity (v_i) is 45m/s and the final velocity (v_f) is 36m/s.

2. From 2.0s to 4.0s: The initial velocity (v_i) is 36m/s and the final velocity (v_f) is 27m/s.

Let's calculate the acceleration for each interval:

1. a = (36m/s - 45m/s) / 2.0s = -4.5 m/s²

2. a = (27m/s - 36m/s) / 2.0s = -4.5 m/s²

So, the acceleration of the object is -4.5 m/s² in both time intervals. This means the object is slowing down at a constant rate.