What is the value of n after the following code is executed?int n = 98;int *p = &n;

Question

What is the value of `n` after the following code is executed?

int n = 98;
int *p = &amp;n;

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Solution

The value of n after the following code is executed would still be 98.

Here's the step by step explanation:

int n = 98; This line declares an integer variable n and initializes it with the value 98.
int *p = &n; This line declares a pointer to an integer p and assigns it the address of n. So, p is now pointing to n.

However, no operation is performed to change the value of n after these lines. Therefore, the value of n remains 98.

This problem has been solved

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