Predict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equation is balanced.→+HBrCaOH2

1. Break Down the Problem

To predict the products of the reaction between calcium hydroxide ($Ca(OH)_2$) and hydrobromic acid ($HBr$), we need to identify the potential acid-base reaction that occurs between these two substances.

2. Relevant Concepts

This is a neutralization reaction where an acid reacts with a base to form a salt and water. The general form of a neutralization reaction can be summarized as:

$\text{Acid} + \text{Base} \rightarrow \text{Salt} + \text{Water}$

In this case:

• Acid: $HBr$
• Base: $Ca(OH)_2$

3. Analysis and Detail

In the reaction $Ca(OH)_2 + 2 HBr$:

• The $Ca(OH)_2$ provides calcium ions ($Ca^{2+}$) and hydroxide ions ($OH^{-}$).
• The $HBr$ provides hydrogen ions ($H^{+}$) and bromide ions ($Br^{-}$).

The reaction can be written as: $Ca(OH)_2 + 2HBr \rightarrow CaBr_2 + 2H_2O$

Here, $CaBr_2$ is the salt formed from the calcium ions and bromide ions, and $H_2O$ is the water produced from the hydroxide ions and hydrogen ions.

4. Verify and Summarize

Let's verify the balance of the equation:

• Reactants side:

  • $Ca(OH)_2$ contributes 1 $Ca^{2+}$ and 2 $OH^{-}$.
  • $2HBr$ contributes 2 $H^{+}$ and 2 $Br^{-}$.

• Products side:

  • $CaBr_2$ contributes 1 $Ca^{2+}$ and 2 $Br^{-}$.
  • $2H_2O$ contributes 4 $H^{+}$ and 2 $OH^{-}$ which forms 2 $H_2O$.

The total counts confirm it is balanced.

Final Answer

The balanced reaction is: $Ca(OH)_2 + 2HBr \rightarrow CaBr_2 + 2H_2O$