Which of these is spontaneous at low temperatures?*A system with ΔHᵒ>0; ΔSᵒ<0A system with ΔHᵒ<0; ΔSᵒ<0A system with ΔHᵒ<0; ΔSᵒ>0A system with ΔHᵒ>0; ΔSᵒ>0
Question
Which of these is spontaneous at low temperatures?
- A system with ΔHᵒ>0; ΔSᵒ<0
- A system with ΔHᵒ<0; ΔSᵒ<0
- A system with ΔHᵒ<0; ΔSᵒ>0
- A system with ΔHᵒ>0; ΔSᵒ>0
Solution
The spontaneity of a reaction can be determined using the Gibbs Free Energy equation: ΔG = ΔH - TΔS.
A reaction is spontaneous if ΔG < 0.
Let's analyze each option:
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A system with ΔHᵒ>0; ΔSᵒ<0: In this case, ΔG = ΔH - TΔS will be positive because both terms are positive (ΔH is positive and -TΔS is also positive because ΔS is negative). So, this reaction is not spontaneous at any temperature.
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A system with ΔHᵒ<0; ΔSᵒ<0: In this case, ΔG = ΔH - TΔS will be negative at low temperatures because ΔH is negative and -TΔS is less negative (because ΔS is negative and T is low). So, this reaction is spontaneous at low temperatures.
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A system with ΔHᵒ<0; ΔSᵒ>0: In this case, ΔG = ΔH - TΔS will always be negative because both terms are negative (ΔH is negative and -TΔS is also negative because ΔS is positive). So, this reaction is spontaneous at all temperatures.
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A system with ΔHᵒ>0; ΔSᵒ>0: In this case, ΔG = ΔH - TΔS will be negative at high temperatures because ΔH is positive and -TΔS is negative but becomes more negative as T increases (because ΔS is positive). So, this reaction is spontaneous at high temperatures.
So, the answer is: A system with ΔHᵒ<0; ΔSᵒ<0 is spontaneous at low temperatures.
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A reaction that leads to a decrease in the free energy of the system is always spontaneous.
If the change in free energy (ΔG) is , the reaction is spontaneous under the conditions specified. If ΔG is , the reaction is not spontaneous.
At what temperature (in K) does the following reaction become spontaneous, if Δ𝐻∘ = 311.1 kJ/mol and Δ𝑆∘ = 707.3 J/mol*K?
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