The assertion is correct. The HC≡C– ion is more stable than the H2C=CH– ion. This is due to the fact that the HC≡C– ion has a higher s-character in its hybridization.

Here's the step-by-step explanation:

1. The hybridization of the carbon atoms in HC≡C– is sp, which means it has 50% s-character and 50% p-character.

2. On the other hand, the hybridization of the carbon atoms in H2C=CH– is sp2, which means it has 33.33% s-character and 66.67% p-character.

3. The s-orbital is closer to the nucleus and thus more stable than the p-orbital. Therefore, the more s-character a molecule has, the more stable it is.

4. Therefore, since HC≡C– has more s-character than H2C=CH–, it is more stable.

So, the reason is correct and it is the correct explanation of the assertion.

Question

The assertion is correct. The HC≡C– ion is more stable than the H2C=CH– ion. This is due to the fact that the HC≡C– ion has a higher s-character in its hybridization.

Here's the step-by-step explanation:

1. The hybridization of the carbon atoms in HC≡C– is sp, which means it has 50% s-character and 50% p-character.

2. On the other hand, the hybridization of the carbon atoms in H2C=CH– is sp2, which means it has 33.33% s-character and 66.67% p-character.

3. The s-orbital is closer to the nucleus and thus more stable than the p-orbital. Therefore, the more s-character a molecule has, the more stable it is.

4. Therefore, since HC≡C– has more s-character than H2C=CH–, it is more stable.

So, the reason is correct and it is the correct explanation of the assertion.

Knowee AI · Accepted Answer

The assertion is correct. The HC≡C– ion is more stable than the H2C=CH– ion. This is due to the fact that the HC≡C– ion has a higher s-character in its hybridization.

Here's the step-by-step explanation:

1. The hybridization of the carbon atoms in HC≡C– is sp, which means it has 50% s-character and 50% p-character.

2. On the other hand, the hybridization of the carbon atoms in H2C=CH– is sp2, which means it has 33.33% s-character and 66.67% p-character.

3. The s-orbital is closer to the nucleus and thus more stable than the p-orbital. Therefore, the more s-character a molecule has, the more stable it is.

4. Therefore, since HC≡C– has more s-character than H2C=CH–, it is more stable.

So, the reason is correct and it is the correct explanation of the assertion.

Assertion : HC ≡ C– is more stable than H2C = CH–Reason : HC ≡ C– has more s-character than H2C = CH–

Question

Assertion : HC ≡ C– is more stable than H2C = CH–

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