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What is the output of the following Python statements?def recurse(a):    if (a == 0):        print(a)    else:        recurse(a)recurse(1)

Question

What is the output of the following Python statements?


def recurse(a):
    if (a == 0):
        print(a)
    else:
        recurse(a)

recurse(1)
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Solution

The provided Python code will result in an infinite recursion error. This is because the function recurse(a) is called within the else clause without modifying the argument a. This means that if a is not initially 0, the function will call itself with the same argument indefinitely.

To avoid this, you should decrease the value of a with each recursive call. Here's an example of how you could modify the function:

def recurse(a): 
    if (a == 0): 
        print(a) 
    else: 
        recurse(a-1)

In this modified version, recurse(1) would output 0 because the function would call itself with the argument 1-1=0, and then print 0.

This problem has been solved

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