What is the output of the following Python statements?def recurse(a): if (a == 0): print(a) else: recurse(a)recurse(1)
Question
What is the output of the following Python statements?
def recurse(a):
if (a == 0):
print(a)
else:
recurse(a)
recurse(1)
Solution
The provided Python code will result in an infinite recursion error. This is because the function recurse(a)
is called within the else
clause without modifying the argument a
. This means that if a
is not initially 0
, the function will call itself with the same argument indefinitely.
To avoid this, you should decrease the value of a
with each recursive call. Here's an example of how you could modify the function:
def recurse(a):
if (a == 0):
print(a)
else:
recurse(a-1)
In this modified version, recurse(1)
would output 0
because the function would call itself with the argument 1-1=0
, and then print 0
.
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