What will be the output of the following program? #include<stdio.h> int main() { int i=10; if (i > 10) else printf ( "Hello Cocaine!" ); return 0; }

Question

What will be the output of the following program?

#include&lt;stdio.h&gt;

int main()
{
    int i=10;
    if (i &gt; 10)
    else
        printf ( &quot;Hello Cocaine!&quot; );

    return 0;
}

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Solution

The code you provided is not correct. It has a syntax error. The if statement is not complete. It should have a condition and a block of code to execute when the condition is true. The corrected code should look like this:

#include<stdio.h>

int main()

{
int i=10;
if (i > 10){
    // some code here
}
else
{
    printf ( "Hello Cocaine!" );
}

return 0;
}

In this corrected code, the printf statement will execute because the condition in the if statement (i > 10) is not true (since i is equal to 10, not greater than 10). So, the output of this program will be: Hello Cocaine!.

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What will be the output of the following program? #include<stdio.h> int main() { int i=10; if (i > 10) else printf ( "Hello Cocaine!" ); return 0; }

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